hpcflow.sdk.submission.types.JobScriptDescriptor#

class hpcflow.sdk.submission.types.JobScriptDescriptor#

Bases: TypedDict

Descriptor for a jobscript.

Methods

clear

copy

fromkeys

Create a new dictionary with keys from iterable and values set to value.

get

Return the value for key if key is in the dictionary, else default.

items

keys

pop

If the key is not found, return the default if given; otherwise, raise a KeyError.

popitem

Remove and return a (key, value) pair as a 2-tuple.

setdefault

Insert key with a value of default if key is not in the dictionary.

update

If E is present and has a .keys() method, then does: for k in E.keys(): D[k] = E[k] If E is present and lacks a .keys() method, then does: for k, v in E: D[k] = v In either case, this is followed by: for k in F: D[k] = F[k]

values

Attributes

resources

Resources required by the jobscript.

elements

Elements handled by the jobscript.

dependencies

Dependencies of the jobscript.

resource_hash

Hash of resources.

clear() None.  Remove all items from D.#
copy() a shallow copy of D#
dependencies: dict[int, hpcflow.sdk.submission.types.ResolvedDependencies]#

Dependencies of the jobscript.

elements: dict[int, list[int]]#

Elements handled by the jobscript.

fromkeys(value=None, /)#

Create a new dictionary with keys from iterable and values set to value.

get(key, default=None, /)#

Return the value for key if key is in the dictionary, else default.

items() a set-like object providing a view on D's items#
keys() a set-like object providing a view on D's keys#
pop(k[, d]) v, remove specified key and return the corresponding value.#

If the key is not found, return the default if given; otherwise, raise a KeyError.

popitem()#

Remove and return a (key, value) pair as a 2-tuple.

Pairs are returned in LIFO (last-in, first-out) order. Raises KeyError if the dict is empty.

resource_hash: str#

Hash of resources.

resources: Any#

Resources required by the jobscript.

setdefault(key, default=None, /)#

Insert key with a value of default if key is not in the dictionary.

Return the value for key if key is in the dictionary, else default.

update([E, ]**F) None.  Update D from mapping/iterable E and F.#

If E is present and has a .keys() method, then does: for k in E.keys(): D[k] = E[k] If E is present and lacks a .keys() method, then does: for k, v in E: D[k] = v In either case, this is followed by: for k in F: D[k] = F[k]

values() an object providing a view on D's values#