hpcflow.sdk.typing.KnownSubmission#
- class hpcflow.sdk.typing.KnownSubmission#
Bases:
TypedDict
Describes a known submission.
Methods
Remove all items from the dict.
Return a shallow copy of the dict.
Create a new dictionary with keys from iterable and values set to value.
Return the value for key if key is in the dictionary, else default.
Return a set-like object providing a view on the dict's items.
Return a set-like object providing a view on the dict's keys.
If the key is not found, return the default if given; otherwise, raise a KeyError.
Remove and return a (key, value) pair as a 2-tuple.
Insert key with a value of default if key is not in the dictionary.
If E is present and has a .keys() method, then does: for k in E.keys(): D[k] = E[k] If E is present and lacks a .keys() method, then does: for k, v in E: D[k] = v In either case, this is followed by: for k in F: D[k] = F[k]
Return an object providing a view on the dict's values.
Attributes
Local ID.
Workflow global ID.
Whether the submission is active.
Submission index.
Submission time.
Path to submission.
Start time.
Finish time.
- clear()#
Remove all items from the dict.
- copy()#
Return a shallow copy of the dict.
- fromkeys(value=None, /)#
Create a new dictionary with keys from iterable and values set to value.
- get(key, default=None, /)#
Return the value for key if key is in the dictionary, else default.
- items()#
Return a set-like object providing a view on the dict’s items.
- keys()#
Return a set-like object providing a view on the dict’s keys.
- pop(k[, d]) v, remove specified key and return the corresponding value. #
If the key is not found, return the default if given; otherwise, raise a KeyError.
- popitem()#
Remove and return a (key, value) pair as a 2-tuple.
Pairs are returned in LIFO (last-in, first-out) order. Raises KeyError if the dict is empty.
- setdefault(key, default=None, /)#
Insert key with a value of default if key is not in the dictionary.
Return the value for key if key is in the dictionary, else default.
- update([E, ]**F) None. Update D from mapping/iterable E and F. #
If E is present and has a .keys() method, then does: for k in E.keys(): D[k] = E[k] If E is present and lacks a .keys() method, then does: for k, v in E: D[k] = v In either case, this is followed by: for k in F: D[k] = F[k]
- values()#
Return an object providing a view on the dict’s values.